If the hypotenuse of a right triangle is known to be 5 and the sum of two right angles is 7, the area of the triangle can be calculated Can you write the process more clearly? This is a big problem
a+b=7
a^2+b^2=25
(a+b)^2=a^2+b^2+2ab=49
So 2Ab = 24
Area = 0.5ab = 6
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