It is known that: as shown in the figure, △ ABC is the inscribed triangle of ⊙ o, ⊙ O's diameter BD intersects AC at e, AF ⊥ BD at F, extending AF intersects BC at g. the proof is AB2 = BG · BC

It is known that: as shown in the figure, △ ABC is the inscribed triangle of ⊙ o, ⊙ O's diameter BD intersects AC at e, AF ⊥ BD at F, extending AF intersects BC at g. the proof is AB2 = BG · BC

Connecting ad, ∵ BD is the diameter of ⊙ o, ∵ bad = 90 °, ∵ BAF + ∵ DAF = 90 °, ∵ AF ⊥ BD, ∵ D + ∵ DAF = 90 °, ∵ bag = ∵ D, ∵ C = ∵ D, ∵ C = ∵ bag, ∵ ABG = ∵ ABC, ∵ ABG ∵ CBA, ∵ AB: CB = BG: AB, ∵ AB2 = BG · BC