In the triangle ABC, the opposite sides of angles a, B and C are a, B and C respectively. We know that a = 2, C = 3 and CoSb = 1 / 4

(1) Finding the value of B
Using the cosine theorem, we get
b^2=a^2+c^2-2*a*c*CosB
Put it into the calculation
b＝√10
(2) Find the value of sinc
Derived from CoSb
SINB=√1-（1/4）^2=√15/4
Sine theorem
b/sinB=c/sinC
Put it into the calculation
sinC=（3√6 ）/8

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