The relationship between the daily water storage capacity of crops in a test field and the growth time is y (kg). The water demand of these crops on the 10th and 30th day is 2000kg and 3000kg respectively. The daily water demand on the 40th day is 100kg higher than that on the previous day When x ≤ 40 and The function of X ≥ 40

[I don't say anything about the relationship. I'm not sure at all. I guess it's proportional here]
y=kx+b
Substituting (102000) and (303000) 2 points to get
2000=10k+b
3000=30k+b
The simultaneous solution is k = 50, B = 1500
When X40, y = yo + 100 (x-40) = 100x-500

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