Seeking derivative of compound function by chain rule H (x) = f [g (x)], f (x) = the square of X, G (x) = 2x

F (x) = the square of X, G (x) = 2x, f '(x) = 2x, G' (x) = 2
h(x)=f[g(x)]
h'(x)=f'[g(x)]g'(x)
=2(2x)(2)=8x

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