A and B leave AB at the same time and meet 45 km away from the midpoint. It is known that a's speed is 1.5 times that of B's. how many km is the distance between AB and B

A walks 45 + 45 km more than B when they meet
When meeting, the distance ratio of car a to car B = speed ratio = 1.5:1 = 3:2
The distance between the two places is 90 ± (3-2) × (3 + 2) = 450 km
The comprehensive formula is
（45+45）÷（1.5-1）×（1.5+1）
=90÷0.5×2.5
=180×2.5
=450 (km)

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