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How does the period of centripetal acceleration and centripetal force change? Does it increase or decrease It's better to have a process The ignorance of random answers (⊙ o ⊙)
The larger the radius is, the greater the linear velocity is. The centripetal force is fixed f = MV ^ 2 / r = MW ^ 2R. So w decreases, and the centripetal acceleration remains unchanged because the centripetal force remains unchanged. The circumference is about 2 π R / V, and V ^ 2 / R remains unchanged. It can be seen that R changes faster than V, so the period becomes larger,
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