Given that a ^ m = 2, a ^ n = 6, m and N are positive integers, find the value of a ^ N-M. division of the same base power: (4x ^ n-1y ^ n + 2) / (- x ^ n-2y ^ n + 1) I'll have it today

Given that a ^ m = 2, a ^ n = 6, m and N are positive integers, find the value of a ^ N-M. division of the same base power: (4x ^ n-1y ^ n + 2) / (- x ^ n-2y ^ n + 1) I'll have it today

Sorry, your formula is wrong. It's hard to understand
It should be a ^ (n-m) = a ^ n / A ^ m = 6 / 2 = 3
So the other one I understand is 4x ^ (n-1) * y ^ (n + 2) / (- x ^ (n-2) * y ^ (n + 1)) = - 4 * x (n-1 - (n-2)) * y ^ (n + 2 - (n + 1)) = - 4xy

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