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What is the formula for measuring acceleration with dot timer?
The acceleration measured by the dot timer is obtained by using the average speed of uniform variable speed motion equal to the instantaneous speed at the middle time
For example, this topic:
As shown in the figure, the paper tape is obtained when the timer is used to study the motion law of free falling body. The interval of the timer is 0.02s, and S1 = 2.73cm, S2 = 3.12cm, S3 = 3.51cm, S4 = 3.90cm, S5 = 4.29cm, S6 = 4.68cm
(1) The velocity of free falling object is VB = & nbsp; - & nbsp; m / s, VF = & nbsp; - & nbsp; m / s when the dot timer hits B and f respectively
(2) The acceleration of free falling object is a = & nbsp; - & nbsp; m / S2 (the result retains three significant digits)
Time interval T = 0.02s
vB=(s1+s2)/2T=(0.0273+0.0312)m/0.04s=1.46m/s
vF=(s5+s6)/2T=(0.0429+0.0468)m/0.04s=2.24m/s
Calculation of acceleration by successive difference method
s4-s1=3a1T²
s5-s2=3a2T²
s6-s4=3a3T²
a=(a1+a2+a3)/3=(s4+s5+s6-s1-s2-s3)/9T²=0.0351/0.0036=9.75m/s²
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