The function f (x) = 2sinx (SiNx + cosx) is given (1 / 2) pro, the function f (x) = 2sinx (SiNx + cosx) is known. Find the minimum positive period of F (x), find the maximum value of F (x) and take

f(x)=2sinx(sinX+cosX)
=2sinxsinx+2sinxcosx
=1-cos2x+sin2x
=√2sin(2x-π/4)+1
So the minimum positive period of F (x) = 2 π / 2 = π
Maximum = 1 + √ 2

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