Given cos (A-wu / 6) + Sina = 4 / 5 times the root 3, then the value of sin (a + 7 Wu / 6) is?

Cos (A-wu / 6) + Sina = √ 3 / 2cosa + 3 / 2sina = √ 3 (1 / 2cosa + √ 3 / 2sina) = (4 √ 3) / 5, so: (1 / 2cosa + √ 3 / 2sina) = 4 / 5 sin (a + 7 / 6) = - sin (a + Wu / 6) = - (√ 3 / 2sina + 1 / 2cosa) = - 4 / 5

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