Question: Let log567 = a denote the following expressions with a (1)log56 8 (2)log56 2 (PS: 56 is base, 8 and 2 and 7 are true)
Because (log56 7) + (log56 8) = (log56 56) = 1
So (log568) = 1-A
Because (log56 8) = 3 (log56 2)
So (log56 2) = (1-A) / 3
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