Given the square of 2x + 1 (Y-2) under the root sign = 0, find the arithmetic square root of the square of x-2xy

The square of 2x + 1 (Y-2) under the root sign = 0
2x+1=0 y-2=0
x=-1/2 y=2
The square of X - 2XY
=(-1/2)^2-2*(-1/2)*2
=1/4+2
=9/4
Square of X - arithmetic square root of 2XY 3 / 2

RELATED INFORMATIONS

1. If the function y = 1 + 2 ＾ x + a.4 ＾ x is greater than zero on (- infinity, 1), the value range of real number a is obtained
2. If the function f (x) = 1 + log (a) x is a decreasing function in the interval (0, positive infinity), then the value range of a?
3. If a is the logarithm of the bottom 3 / 4 < 1, (a > 0 and a is not equal to 1), find the value range of the real number a?
4. If three fourths of loga is less than 1, what is the range of a?
5. If loga (12 / A-1) < 1, then the value range of a is
6. If loga (a + 2) > loga (a + 1), then the value range of a is___ .】 +∞）
7. If loga (A2 + 1)
8. loga(2/3)
9. If loga23 > 1, then the value range of a is______ ．
10. When 0 ＜ X & # 171; 0.5 and 4 ＜ loga (x), what is the value range of a
11. Given | x + y + 4 | + √ [(X-2) & sup2;] = 0, find the square root of x power of Y Tick [~] is the root sign,
12. It is known that 10 ＋ 3 = x + y, where x is an integer and 0
13. Given 10 + 3 = x + y, where x is a positive integer and 0 < y < 1, find the opposite number of X-Y
14. Why lg5 · LG20 = lg5 (2lg2 + lg5) See the answer is written like this, but I even to (1 + LG2) (1 - LG2), ask for detailed explanation
15. Given that the power function satisfies: X ≥ 4, then f (x) = (1 / 2) ^ X; when x < 4, f (x) = f (x + 1), then f (2 + L, logarithm of 3 with 2 as the base) is,
16. Given that the function f (x) is a piecewise function, when x is greater than or equal to 0, f (x) = x ^ 2 + 1, when x is less than 0, f (x) = 1. Then the range of X satisfying the inequality f (1-x ^ 2) > F (2x) is?
17. Why is a function f (x) equal to the LNF (x) power of E
18. (3) Logamn = nlogam (n ∈ R). How to prove this
19. The derivation of logarithm operation property 3 Use ^ to express the power and log (a) (b) to express the logarithm of B with a as the base log(a)(M^n)=nlog(a)(M) I want to know the derivation process of this formula!
20. (1) It is proved that Logan = logcnlogca (where a ＞ 0, a ≠ 1, n ＞ 0, C ＞ 0, C ≠ 1). (2) let a and B be positive numbers not equal to 1, it is proved that loganbm = mnlogab (m ∈ R, & nbsp; n ∈ R, & nbsp; n ≠ 0)