: when x takes what value, the value of the following function is zero (1) y = - 5 + 3x (2) y = 2x & # 178; - 5x + 3 (3) y = x-3 of X-1 The point is the third question. Because I don't understand. It's better to be clear

: when x takes what value, the value of the following function is zero (1) y = - 5 + 3x (2) y = 2x & # 178; - 5x + 3 (3) y = x-3 of X-1 The point is the third question. Because I don't understand. It's better to be clear

(1)y=-5+3x
-5+3x=0
3x=5
x=5/3
In fact, the method of (1) (2) (3) is to take out the formula after y = and then = 0, and then continue to calculate