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It is known that an ellipse with 4 / 2 of x plus 3 / 2 of Y equals 1, and a parabola with y equals 4x square Find the focal length of ellipse. 2, find the focal coordinate of parabola and the equation of collimator
According to the elliptic equation, a ^ 2 = 4, B ^ 2 = 3, so C ^ 2 = 1, so the focus coordinates are (C, 0), (- C, 0), that is (- 1,0) and (1,0),
Focal length = 2
X ^ 2 = 1 / 4Y to x ^ 2 = 2PY
Focus coordinate (0,1 / 16), quasilinear equation y = - 1 / 16
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