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2-channel acute angle trigonometric function calculation, 4cos^2a-2(1+√3)cosa+√3=0 2cos^2a+3√3sina-5=0 Find the acute angle a satisfying the following conditions
4cos^2a-2(1+√3)cosa+√3=0
(2cosa-1)(2cosa-√3)=0
cosa=1/2,cosa=√3/2
So a = 60 degrees, a = 30 degrees
2cos^2a+3√3sina-5=0
2(1-sin^2a)+3√3sina-5=0
2sin^2a-3√3sina+3=0
(2sina-√3)(sina-√3)=0
√3>1
So Sina = √ 3 doesn't hold
So Sina = √ 3 / 2
So a = 60 degrees
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