How much is 2sin60

2sin60°
=2 × 2 √ 3
=√3

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1. A problem of tan45-cot15 tan45=1 cot15=tan75 The original formula = (tan45-tan75) / (1 + tan75) =(tan45-tan75)/(1+tan45tan75) =tan(45-75) =tan(-30) =-√3/3 How does the original formula = (tan45-tan75) / (1 + tan75) become the following one =(tan45-tan75)/(1+tan45tan75)
2. Tan45 = 1, conversely, 1 equals tan45 degrees
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11. What's the meaning of 3tan 30, 3cos 45 and 2Sin 60
12. 3tan30°-cot45°+2sin60°+cos60°=?
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