A and B set out from a and B at the same time. A rode a bicycle, B drove a car, and drove along the same route at a constant speed. After three hours of departure, they met. It is known that B traveled 90 kilometers more than a when they met, and arrived at a after 1:00. What are the speeds of a and B?

As shown in the figure, let B's speed be x km / h, and the meeting point be C, then BC = x km, AC = x + 90. From: 3x = x + 90, we can get: x = 45. So: A's speed is 453 = 15 km / h, B's speed is 45 km / h. answer: A's speed is 15 km / h, B's speed is 45 km / h

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