The solution of inequality loga ^ (x ^ 2-5x + 6) & lt; loga ^ (2x-2) 0 & lt; a & lt; 1 for | x + B | & lt; 3 is known

The solution of inequality loga ^ (x ^ 2-5x + 6) & lt; loga ^ (2x-2) 0 & lt; a & lt; 1 for | x + B | & lt; 3 is known

Solution;
In the first inequality, under the condition of X + 3 > 0 and x ^ 2-3x + 2 ≥ 0, the two sides of the inequality are squared to x ^ 2-3x + 2-7 / 9
The solution set is (- 7 / 9,1] ∪ [2, + ∞)
The second inequality, because 00 gives (1, (7 - √ 17)) ∪ ((∞), (7 + √ 17) / 2)
The third inequality is - 3 without the sign of absolute value