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It is known that the function f (x) is defined as an increasing function f (2) = 1, f (XY) = f (x) + F (y) defined on greater than 0, which solves the inequality f (4) f (X-2) less than or equal to 3
Is the title wrong?
If f (4) + F (X-2) ≤ 3, please see:
f(4)=f(2*2)=f(2)+f(2)=2
So:
f(8)=f(4*2)=f(4)+f(2)=2+1=3
So:
Find f (4) + F (X-2) ≤ 3
That is to say:
f(4)+f(x-2)≤f(8)
f(4(x-2))≤f(8)
Because the function f (x) is defined as an increasing function over 0
So:
4(x-2)≤8
x≤4
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