If f (x) = ax ^ 2 + BX + C, then "f (m) f (n)

First of all, the front can be pushed to the back, so it is a sufficient condition;
But the latter cannot be pushed to the front, because there may be two zeros in the middle of (m, n), so that the product of function values is greater than zero

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1. If the function f (x) = 4x ^ 2-mx + 5 is an increasing function in the interval [- 2, positive infinity), then the value range of F (1) is
2. Given that the function f (x) = 4x2-mx + 5 is an increasing function in the interval [- 2, + ∞), then the value range of M is () A. （-∞，-16）B. （-∞，16]C. （-∞，-16]D. （4，16）
3. 2. Given that the function f (x) = 4x ^ 2-mx + 5 is an increasing function in the interval [- 2, positive infinity), then the value range of F (1) is a, ≥ 25B, = 25C, ≤ 25d, I don't understand why x = - B / 2A ≤ - 2, that is, M / 8 ≤ - 2, m ≤ - 16 Why is x = - B / 2A greater than or equal to - 2?
4. Given that the function f (x) = 4x ^ 2-mx + 5 is an increasing function in the interval [- 2, negative infinity), then the value range of F (1) is It's on [- 2, positive infinity)
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