Given that inequality 2a-5x > 2x-1 holds for any x ∈ [0,1], then the value range of real number a is? Please provide a variety of solutions

If x ∈ [0,1 / 2] and 2x-1 = 0, then 2a-5x > 2x-1 or 2a-5x2x-1 leads to a > (7x-1) / 2. If x ∈ [1 / 2,1] is constant, X must take the maximum value of 1
Then a > 3
2a-5x

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