Given the set a = {x Ⅰ X & sup2; + (P + 2) x + 1 = 0, X ∈ r}, if a ∩ R + = empty set, find the value range of real number P
A ∩ R + = empty set, indicating that the equation x & sup2; + (P + 2) x + 1 = 0 has no positive root
There are two situations
(1) A = empty set
The equation has no solution and the discriminant is less than 0
(p+2)²-4
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