Given the function f (x-1) = x2-3x + 2, find f (x + 1)

Because f (x-1) = (x-1) ^ 2 - (x-1)
So f (x) = x ^ 2-x
So f (x + 1) = (x + 1) ^ 2 - (x + 1)
=x^2+x
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