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It is known that f (x) is a first-order function, which satisfies 3f (x + 1) - 2F (x-1) = 2x = 17
f(x)=ax+b
3f(x+1)-2f(x-1)
=3[a(x+1)+b]-2[a(x-1)+b]
=3ax+3a+3b-2ax+2a-2b
=ax+5a+b
=2x+17
a=2,b=7
f(x)=2x+7
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