Given that the 8N power of 3 = 2, find the - n-1 power of 9 times the - 2n power of 27

Given that the 8N power of 3 = 2, find the - n-1 power of 9 times the - 2n power of 27

3^(8n)=2
9^(-n-1)×27^(-2n)
=3^[2(-n-1)]×3^[3(-2n)]
=3^[2(-n-1)+3(-2n)]
=3^(-8n-2)
=1/3^(8n+2)
=1/[3^(8n) ×3^2]
=1/(2×9)
=1/18