Finding the minimum positive period of function {process} FX=sin{2x+PI/6}+sin{2x-pi/6}+cos2x

F (x) = [sin (2x + π / 6) + sin (2x - π / 6)] + cos (2x) = 2Sin {[(2x + π / 6) + (2x - π / 6)] / 2} cos {[(2x + π / 6) - (2X - π / 6)] / 2} + cos (2x) = 2Sin (2x) cos (π / 6) + 2cos (2x) sin (π / 6) = 2Sin (2x + π / 6) where amplitude A = 2, angular frequency ω = 2, initial phase φ 0 = π / 6, SiNx

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