If the real part and imaginary part of complex number 2 − BI1 + 2I (B ∈ R) are opposite to each other, then B = () A. 2B. 23C. −23D. 2

If the real part and imaginary part of complex number 2 − BI1 + 2I (B ∈ R) are opposite to each other, then B = () A. 2B. 23C. −23D. 2

∵ complex 2 − BI1 + 2I = (2 − BI) (1 − 2I) (1 + 2I) 1 − 2I) = 2 − 2B − (B + 4) i5 = 2 − 2B5 + − 4 − b5i. From the meaning of the title, we can get 2 − 2B5 = - - 4 − B5, and the solution is b = - 23