The electromotive force of the power supply is e = 12V, and the internal resistance R = 0.5 Ω. A bulb with rated voltage of 8V and rated power of 16W is connected with a bulb with coil resistance R of 0.5 Ω After the DC motor is connected in parallel with the power supply, the bulb just lights normally, and the total current is calculated ① U motor = u bulb = 8V = u external circuit ﹥ u internal circuit = E-U external circuit = 4V ﹥ total current = 4V ﹥ 0.5eu = 8A ② R outer = 4 × 0.5 △ 4 + 0.5 = 4 / 9 total current = E / (4 / 9 + 0.5) = an extra large fraction Why are the numbers calculated different? Why is the second method wrong?

The electromotive force of the power supply is e = 12V, and the internal resistance R = 0.5 Ω. A bulb with rated voltage of 8V and rated power of 16W is connected with a bulb with coil resistance R of 0.5 Ω After the DC motor is connected in parallel with the power supply, the bulb just lights normally, and the total current is calculated ① U motor = u bulb = 8V = u external circuit ﹥ u internal circuit = E-U external circuit = 4V ﹥ total current = 4V ﹥ 0.5eu = 8A ② R outer = 4 × 0.5 △ 4 + 0.5 = 4 / 9 total current = E / (4 / 9 + 0.5) = an extra large fraction Why are the numbers calculated different? Why is the second method wrong?

The motor is not a pure resistance circuit, so Ampere's law cannot be used