The least common multiple of the three primes is 70. The three primes are (), () and ()
70=2×5×7
So it's two, five, seven
RELATED INFORMATIONS
- 1. The least common multiple of the three prime numbers is 78, which are (), (), ()
- 2. The least common multiple of two primes is 111. What are the two and how many
- 3. The least common multiple of two primes is 91, and the sum of the two primes is______ .
- 4. The maximum factor of a number is 2001, and the minimum multiple of the number is (). The sum of two prime numbers is 2001, and the product of the two prime numbers is ()
- 5. If () has two factors, such a number is called prime or (). The smallest prime is ()
- 6. A number () and two factors () are called prime numbers
- 7. If both numbers are prime, then their product has a factor
- 8. 511 is not a prime number. Which two numbers' product = 511?
- 9. The product of two prime numbers is 94, the sum of these two prime numbers is (), and their greatest common factor is ()
- 10. The product of two primes is 94, and the sum of the two primes is______ .
- 11. The least common multiple of three different prime numbers is 154, which are (), (), ()
- 12. The least common multiple of the three prime numbers is 114. What are the three numbers?
- 13. The least common multiple of the three primes is 70. The three primes are______ .
- 14. Let Z1 = 1 + 2ai, Z2 = A-I (a ∈ R), a = {Z | z-z1|
- 15. Let Z and Z1 be conjugate complex numbers, and (Z + z1) & sup2; - 3Z * z1i = 4-6i Finding complex numbers Z and Z1
- 16. If Z1 = 2-5i, Z2 = - 4 + 3I, then Arg (z1 + Z2)=
- 17. Find the complex Z satisfying the following conditions (1) Absolute value Z-Z = 10-1-2i (2) z^2=7+24i The z-handle of (1) is a conjugate complex number. I'm sorry
- 18. Find all complex numbers Z satisfying the following conditions at the same time (1) 1<(z+10/z)≤6 (2) The real part and imaginary part of Z are all integers The second problem is "the real part and imaginary part of Z are all integers, so we can find the complex Z satisfying the condition."
- 19. If z = 2-I, then (Z -) + 10 / Z= (Z -) is actually trying to hit Z with a cross
- 20. If the complex Z satisfies the equation Z2 + 2 = 0, Z2 =? dial the wrong number. What is Z3?