Given that the a power of 3 is equal to 4 and the B power of 3 is equal to 2, then what is the (2a + 3b) power of 3?
3^(2a+3b) =3^(2a) * 3^(3b) = [(3^a)^2] * [(3^b)^3] = [(4)^2] * [(2)^3] =16 * 8=128
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