Given that there is only one element in the set a = {x | (A-1) x ^ 2 + 3x-2 = 0}, we can find the value of real number a
1)a-1=0 a=1
x=2/3
2)b²-4ac=9-4(a-1)(-2)=0
a=-1/8
RELATED INFORMATIONS
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