It is proved that Cu (a + b) = CUA + cub The answer should be detailed, the process should be standard, and it's better to understand. Few of us can understand what our math teacher said

It is proved that Cu (a + b) = CUA + cub The answer should be detailed, the process should be standard, and it's better to understand. Few of us can understand what our math teacher said

For example, let the complete set be {1,2,3,4,5}, a = {1,2,3}, B = {3,4,5}, then CUA = {4,5}, Cub = {1,2} CUA ∪ cub = {1,2,4,5} and a ∩ B = {3}, Cu (a ∩ b) = {1,2,4,5} = CUA ∪ cub

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