If 10 ^ a = (1 / 3) ^ - 2, 10 ^ B = 4 ^ - 1, try to find the value of 9 ^ A / 3 ^ 2B 2006 ^ 2-2006 * 4010 + 2005 ^ 2 | Math enthusiast | Mathematical art

If 10 ^ a = (1 / 3) ^ - 2, 10 ^ B = 4 ^ - 1, try to find the value of 9 ^ A / 3 ^ 2B 2006 ^ 2-2006 * 4010 + 2005 ^ 2

(1) The title is not very clear
(2) 2006^2-2006*4010+2005^2=2006^2-2*2006*2005+2005^2=(2006-2005)^2=1

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