3x & sup2; - 7xy-20y & sup2; to prove x = 4Y or 3x = - 5Y, there is another question 49 (x-3) & sup2; = 16 (x + 6) & sup2;

3x & sup2; - 7xy-20y & sup2; to prove x = 4Y or 3x = - 5Y, there is another question 49 (x-3) & sup2; = 16 (x + 6) & sup2;

3x & # 178; - 7xy-20y & # 178; = 0 (x-4y) (3x + 5Y) = 0x = 4Y or 3x = - 5y49 (x-3) & # 178; = 16 (x + 6) & # 178; 49 (x-3) & # 178; - 16 (x + 6) & # 178; = 0 (7x-21 + 4x + 24) (7x-21-4x-24) = 0 (11x + 3) (3x-45) = 0x1 = - 3 / 11x2 = 15