[1 / 15] + [2 / 15] + [3 / 15] + [4 / 15] +. + [n-1 / 15] + [n / 15] > 2011 find the minimum value of n Write down the method Please!

[1/15]+[2/15]+[3/15]+[4/15]+.+[n-1/15]+[n/15]
=（1+2+3+4+-----+（n-1)+n）/15=（n+1)n/（2*15）
=（n+1)n/30>2011,
N & sup2; + n > 60330, (n + 1 / 2) & sup2; > 60330 + 1 / 4, because 251 & sup2;

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