The cyclist rides on a 30 m long slope at an initial speed of 5 m / S2 per second, and the acceleration is 0.4 m / S2

Solution 1:
Vo=5m/s,a=-0.4m/s^2,S=30m
S=Vot+(1/2)at^2
30=5t-0.5*0.4t^2
t1=10s
When T2 = 15s, V

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