There is an object moving in a straight line with constant acceleration at an initial velocity of 0 and an acceleration of 10 meters every second, reaching 2M and 4m Then V1: V2 is equal to
V^2-V0^2=2ax
Substituting formula
V^2-0^2=2*10*2
The solution is v = 40, which is the velocity at two meters, which is V1 velocity
V^2-V0^2=2ax
Substituting formula
V^2-0^2=2*10*4
The solution is v = 80, which is the velocity at four meters, which is V2 velocity
V1: V2 is equal to 1:2
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