A car is waiting for the green light at the intersection. When the green light is on, the car starts to accelerate at an acceleration of 3m / S2. Just at this time, a bicycle comes at a constant speed of 6m / s and overtakes the car from behind? What is the distance at this time? (2) How long will the car catch up with the bike? How fast is the car when catching up?

A car is waiting for the green light at the intersection. When the green light is on, the car starts to accelerate at an acceleration of 3m / S2. Just at this time, a bicycle comes at a constant speed of 6m / s and overtakes the car from behind? What is the distance at this time? (2) How long will the car catch up with the bike? How fast is the car when catching up?

(1) Suppose that the speed of two cars is equal in t time before the car overtakes the bicycle, then the distance between the two cars is the farthest, that is, at = V from, the solution is: T = V from a = 63s = 2S, at this time, the distance △ s = s2-s1 = v from t-12at2, △ s = 6 × 2-3 × 12 × 3 × 22 = 6m; & nbsp; & nbsp; & nbsp; & nbsp; (2) when the car overtakes the bicycle