Given the point m (1-A, 2A + 2), if the symmetric point of point m about X axis is in the third quadrant, then the value range of a is in the third quadrant______ ．

∵ the symmetric point of point m (1-A, 2A + 2) about X axis is in the third quadrant, ∵ point m is in the second quadrant, ∵ 1 − a < 02A + 2 > 0, the solution is: a > 1, so the answer is: a > 1

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