It is known that the solution of the equation 2x + 12 = 4a-3x about X is a non negative number, and the value range of a is obtained
2X + 12 = 4a-3x, then 5x + 12 = 4A, x = 4a-12 / 5, X is greater than or equal to 0, then a is greater than or equal to 3
RELATED INFORMATIONS
- 1. If the solution of equation 5 (A-1) = 3A + X-11 is nonnegative, then the value range of a is?
- 2. If the solution of the equation 3a-4x = 6 of X is nonnegative, then the value range of a is
- 3. The two of the equation x ^ 2 + 2 (P + 1) x + 2p-5 = 0 are both negative numbers. The value range of the real number P is obtained
- 4. It is known that the equation x ^ 2-4x + 2a-6 = 0 about X has a negative solution, so we can find the value range of the real number a
- 5. The combination a consists of the solution of the equation AX & # 178; - 2x + 1 = 0. 1. If the set a is an empty set, find the value range of the real number a 2. If there is only one element in the set a to find the value of a, I hope you can help me. I'm not good at math. I'm a beginner
- 6. If the two roots of the equation X2 (is square) + (T-2) x + 5-T = 0 of X are greater than 2, then the value range of T is________
- 7. If the two real number roots of the equation x2 + (M-3) x + M = 0 about X are unequal positive numbers, then the value range of real number m is______ .
- 8. If α and β are the two real roots of the equation x + 2x-2010 = 0, find the square of α + 3 α + β Factorization in real numbers: the square of 1-xy-4x, the square of Y Solution equation: (2-radical 3) square of X-2 (radical 3-1) X-6 = 0
- 9. The equation AX2 + 2x + 1 = 0 has at least one negative real root if and only if () A. 0 < a < 1b. 0 < a ≤ 1 or a < 0C. 0 ≤ a ≤ 1D. A ≤ 1
- 10. Proof: the equation x2 + MX + 1 = 0 of X has two negative real roots if and only if M ≥ 2
- 11. Given that the root of the linear equation 3x-m + 1 = 2x-1 is negative, then the value range of M is______ .
- 12. If the root of the equation MX + 1 = 3x-3 about X is negative, then the value range of M?
- 13. If the solution of equation a (3x-1) = 2x-5 is negative, find the value range of Adu. Big brother and big sister help me. I need the answer and process before 12:40
- 14. If the solution of the equation 3x-m + 1 = 2x-1 is negative, then the range of M is
- 15. If the solution of the equation 3x-m = 5-2x about X is a negative number, then the value range of M is
- 16. It is known that the solution of the equation 2a-1 / 2x = 7 / 2x + 3 about X is negative
- 17. When k takes what value, the equation X-1 / 5 (3x + k) + 1 / 2 (2x + 7K) = 3-1 / 2 (x-6k) has negative solution?
- 18. When k is a value, the solution of the equation 3-2x-3k = 5 (x-k) + 1 is: positive; negative; zero
- 19. If the solution of the equation 2x-7k = 5 (x-k) - 4 about X is nonnegative, find the value of positive integer K
- 20. It is known that the solution X of the system of equations X-Y = 3,2x + y = 6a is nonnegative and Y is less than 3