The math problems in volume two of junior high school are due this afternoon Sorry, I don't have points, so I can't give points. But I hope you can help me solve it 1. If an inner angle of a polygon with equal angles is n times of its outer angle, then the number of sides of the polygon is () A. It doesn't exist B、2N+2 C、2N-1 D. None of the above is true 2. In △ ABC, BP bisects ∠ B and CP bisects ∠ C. If ∠ a = 60 degrees, ∠ BPC = () 3. If the sum of interior angles of a polygon is 1260 degrees, then there are () diagonals passing through a vertex of the polygon 4. (n-k) M = ()

The math problems in volume two of junior high school are due this afternoon Sorry, I don't have points, so I can't give points. But I hope you can help me solve it 1. If an inner angle of a polygon with equal angles is n times of its outer angle, then the number of sides of the polygon is () A. It doesn't exist B、2N+2 C、2N-1 D. None of the above is true 2. In △ ABC, BP bisects ∠ B and CP bisects ∠ C. If ∠ a = 60 degrees, ∠ BPC = () 3. If the sum of interior angles of a polygon is 1260 degrees, then there are () diagonals passing through a vertex of the polygon 4. (n-k) M = ()

1. A: B
Polygon interior angle and 180 (number of sides - 2)
Polygon outer corner and 360
Because an inner angle is n times its outer angle and all the angles are equal
So 180 (number of sides - 2) / 360 = n
Number of sides = 2n-2
2.120 degrees
3.180(n-2)=1260 n=9
4.k=5,m=3,n=?
It seems that there is no n-polygon with six diagonals, right?