If the polynomial x2-3kxy-3y2 + 6xy-8 contains no XY term, then K=______ ．

The original formula = x2 + (- 3K + 6) xy-3y2-8, because there is no XY term, so - 3K + 6 = 0, the solution is: k = 2, so the answer is: 2

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