3 {x} ^ {2} + kxy-8 {y} ^ {2} divided by x-2y, the quotient is 3x + 4Y, then the value of K is?

∵(x-2y)(3x+4y)=3x²-2xy-8y²
∴3x²+kxy-8y²=3x²-2xy-8y²
∴k=-2
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