1 / A-3 minus 1 / a square-9 minus A-1 / 6 + 2A
1/(a-3)-1/(a^2-9)-1/(6+2a)
=【(a+3)-1-(a-3)/2】/(a^2-9)
=(a-5)/[2*(a+3)(a-3)]
RELATED INFORMATIONS
- 1. (2a square minus 2 / 3 a minus 4 / 9) times (- 9a)
- 2. Calculation: (- a 2 / 4) + (2-A 1 / 4)
- 3. Given that the square of 2a is equal to 3 and the square of 3b is equal to 2, find the value of ab Then find the value of (2 ^ 2A + 3 ^ 3b) (2 ^ 2a-3 ^ 3b)
- 4. If 2A = 3b, then the square of 2A / the square of 3b is equal to, why
- 5. What is the square of (2a + 3b) multiplied by the square of (2a-3b)
- 6. How to calculate the negative square of (2a + b) Please, the teacher is really, in the first volume when teaching the second volume, do not know
- 7. Calculation: (- C / 2A square B)
- 8. Calculation (2a + B-C) (2a + B + C)
- 9. (A-3) square - (2a-6) = ()
- 10. (square of a-2a) (square of a-2a-6) + 9
- 11. (urgent) x, y and Z are real numbers which are not all zero. The denominator is the square of X + the square of Y + the square of Z, and the numerator is XY + 2yz Function part It's all wrong. It's different from the answers at the back of the book.
- 12. What is the maximum value of three positive real numbers (XY + 2yz) / (the square of X + the square of Y + the square of Z)
- 13. If real numbers x, y, Z satisfy x2 + Y2 + Z2 = 1, then the maximum value of XY + YZ is___ .
- 14. Mathematics problems in grade one of junior high school (solving equations and calculating) (1) To solve the equation: 150x/(1-60%)=150(x+20)/(1-15%) (2) Calculation: 48+20-[12000*(1-20%)/150] [Note: solving equations and calculating need to write process]
- 15. The equations 2x − y = − 33x + y = 8 and ax + by = 2aX − by = 4 have the same solution, and the values of a and B are obtained
- 16. Given that {x = 3, y = 1 and {x = 2, y = 11 are solutions of AX + by = 7, what are the values of a and B?
- 17. Given that x = - 2 is the solution of the equation AX ^ 2 - (2a-3) x + 5 = 0, find the value of A
- 18. The equation 3 (AX-2) - (x + 1) = 2 (1 / 2 + x) 1) Only one solution? 2) no solution?
- 19. Given that x = 4 is the solution of the equation AX-1 = 3 (x + a) about X, find the value of A
- 20. It is known that the system of linear equations ax-2t = 1,3x + 4Y = 5 with respect to X and y has no solution Finding the value of a