Determine whether the circle x ^ 2 + y ^ 2-6x + 4Y + 12 = 0 is tangent to the circle x ^ 2 + y ^ 2-14x-12y + 14 = 0?

X2+Y2-6X+4Y+12=0,
(x-3) & sup2; + (y + 2) & sup2; = 1 & sup2; the center of the circle is (3, - 2) and the radius is 1
X2+Y2-14X-2Y+14=0
(X-7) & sup2; + (Y-1) & sup2; = 6 & sup2; the center of the circle is (7,1) and the radius is 6
The center distance is 5,
So the two circles are inscribed!

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