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Let the image of function f (x) = LX + 2L + LX al be symmetric with respect to the line x = 1, then the value of a is? Urgent method idea!
From F (2-x) = f (x), we can see that the function is symmetric with respect to x = 1,
Therefore, we only need 2-x instead of X to coincide, f (2-x) = | 4-x | + | x + A-2|
That is, when a = 4, the function is consistent
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