Solving the equation: one part of x minus one part of X + one part of 5 equals 5

If x ≠ 0 and X ≠ - 5, then the original equation can be reduced to [x (x + 5)] (x + 5-x) = 5 [x (x + 5)] 5 = 5 [x (x + 5)] 1 = 1, then: X (x + 5) = 1 x square + 5 x = 1 x square + 5 x + 25 / 4 = 1 + 25 / 4 (x + 5 / 2) square = 29 / 4. The solution is: x = (- 5 + radical 29) / 2 or x = (- 5 - radical 29) / 2

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