Given 1 + 2 + 3 +. + 33 = 17 * 33, find 1-3 + 2-6 + 3-9 + 4-12 +... + 31-93 + 32-96 + 33-99 bang wo

Given 1 + 2 + 3 +. + 33 = 17 * 33, find 1-3 + 2-6 + 3-9 + 4-12 +... + 31-93 + 32-96 + 33-99 bang wo

(1) Summation formula: (first term + last term) * number of terms / 2
Number of items = (last first) / tolerance + 1
(99-3)/3+1=33
3+6+9+… +93+96+99=(3+99)*33/2=51*33
1+2+3+.+33=17*33
1-3+2-6+3-9+4-12+...+31-93+32-96+33-99=17*33-51*33=-34*33=-1122
(2)3+6+9+… +93+96+99=3*(1+2+3+.+33)=3*17*33
1-3+2-6+3-9+4-12+...+31-93+32-96+33-99=17*33-3*17*33=-2*17*33=-1122
I don't know if it's right