Given 3 / a = 4 / b = 5 / C, find the value of the square of AB BC + AC / A + the square of B + the square of C
If 3 / a = 4 / b = 5 / C = 1 / T, then a = 3TB = 4tc = 5tab BC + AC / A's square + B's square + C's Square = (AB BC + AC) / (a ^ 2 + B ^ 2 + C ^ 2) = (3T * 4t-4t * 5T + 3T * 5T) / (9t ^ 2 + 16t ^ 2 + 25t ^ 2) = (3 * 4-4 * 5 + 3 * 5) / (
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